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Rust errors / Types and traits

Rust compiler error · checked with rustc 1.99.0

Rust error E0561: patterns aren't allowed in function pointer types

What it meansA non-ident or non-wildcard pattern has been used as a parameter of a function pointer type.

What rustc prints

error[E0561]: patterns aren't allowed in function pointer types
 --> main.rs:1:14
  |
1 | type A1 = fn(mut param: u8); // error!
  |              ^^^^^^^^^

Real output of rustc 1.99.0 compiling the official example below (2021 edition). Your names and line numbers will differ; the first line is the part to match.

E0561Types and traits
Activein rustc 1.99.0
8related errors linked below

The compiler team's explanation

A non-ident or non-wildcard pattern has been used as a parameter of a function pointer type.

Erroneous code example:

type A1 = fn(mut param: u8); // error!
type A2 = fn(&param: u32); // error!

When using an alias over a function type, you cannot e.g. denote a parameter as being mutable.

To fix the issue, remove patterns (_ is allowed though). Example:

type A1 = fn(param: u8); // ok!
type A2 = fn(_: u32); // ok!

You can also omit the parameter name:

type A3 = fn(i16); // ok!

From rustc --explain E0561 (1.99.0), part of the Rust project, MIT or Apache-2.0. Official page.

Related errors

All 518 Rust error codes · Rust crate data · Glossary

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