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Rust errors / Ownership and borrowing

Rust compiler error · checked with rustc 1.99.0

Rust error E0491: in type `&'a Foo<'b>`, reference has a longer lifetime than the data it references

What it meansA reference has a longer lifetime than the data it references.

What rustc prints

error[E0491]: in type `&'a Foo<'b>`, reference has a longer lifetime than the data it references
  --> main.rs:10:5
   |
10 |     type Out = &'a Foo<'b>; // error!
   |     ^^^^^^^^
   |
note: the pointer is valid for the lifetime `'a` as defined here
  --> main.rs:9:6
   |
 9 | impl<'a, 'b> Trait<'a, 'b> for usize {
   |      ^^
note: but the referenced data is only valid for the lifetime `'b` as defined here
  --> main.rs:9:10
   |
 9 | impl<'a, 'b> Trait<'a, 'b> for usize {
   |          ^^

Real output of rustc 1.99.0 compiling the official example below (2021 edition). Your names and line numbers will differ; the first line is the part to match.

E0491Ownership and borrowing
Activein rustc 1.99.0
8related errors linked below

The compiler team's explanation

A reference has a longer lifetime than the data it references.

Erroneous code example:

struct Foo<'a> {
    x: fn(&'a i32),
}

trait Trait<'a, 'b> {
    type Out;
}

impl<'a, 'b> Trait<'a, 'b> for usize {
    type Out = &'a Foo<'b>; // error!
}

Here, the problem is that the compiler cannot be sure that the 'b lifetime will live longer than 'a, which should be mandatory in order to be sure that Trait::Out will always have a reference pointing to an existing type. So in this case, we just need to tell the compiler than 'b must outlive 'a:

struct Foo<'a> {
    x: fn(&'a i32),
}

trait Trait<'a, 'b> {
    type Out;
}

impl<'a, 'b: 'a> Trait<'a, 'b> for usize { // we added the lifetime enforcement
    type Out = &'a Foo<'b>; // it now works!
}

From rustc --explain E0491 (1.99.0), part of the Rust project, MIT or Apache-2.0. Official page.

Related errors

All 518 Rust error codes · Rust crate data · Glossary

Up next

Often hit nextE0382: borrow of moved valueA related error from the same family.Read it next →

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